Đáp án:
\(\begin{array}{l}
\% {V_{{C_2}{H_4}}} = 28,75\% \\
\% {V_{C{H_4}}} = 71,25\%
\end{array}\)
Giải thích các bước giải:
\(\begin{array}{l}
a)\\
{C_2}{H_4} + B{r_2} \to {C_2}{H_4}B{r_2}\\
b)\\
{n_{B{r_2}}} = \dfrac{{9,2}}{{160}} = 0,0575mol\\
{n_{{C_2}{H_4}}} = {n_{B{r_2}}} = 0,0575mol\\
{V_{{C_2}{H_4}}} = 0,0575 \times 22,4 = 1,288l\\
\% {V_{{C_2}{H_4}}} = \dfrac{{1,288}}{{4,48}} \times 100\% = 28,75\% \\
\% {V_{C{H_4}}} = 100 - 28,75 = 71,25\%
\end{array}\)