Giải thích các bước giải:
e.$\dfrac{3x-4}{5}-\dfrac{3+x}{4}=\dfrac{x+1}{10}$
$\to4\left(3x-4\right)-5\left(x+3\right)=2\left(x+1\right)$
$\to 7x-31=2x+2$
$\to 5x=33$
$\to x=\dfrac{33}5$
f.$\dfrac{x+2}{3}+\dfrac{3(2x-1)}{4}-\dfrac{5x-3}{6}=\dfrac{x+5}{12}$
$\to 4\left(x+2\right)+9\left(2x-1\right)-2\left(5x-3\right)=x+5$
$\to 12x+5=x+5$
$\to 11x=0$
$\to x=0$