\(\begin{array}{l}
a)\\
nC{O_2} = \frac{{0,88}}{{44}} = 0,02mol\\
n{H_2}O = \frac{{0,36}}{{18}} = 0,02\,mol\\
mC + mH = 0,02 \times 12 + 0,04 \times 1 = 0,28g\\
= > mO = 0,6 - 0,28 = 0,32g\\
nO = 0,32/16 = 0,02mol\\
nC:nH:nO = 0,02:0,04:0,02 = 1:2:1\\
= > CTPTA:C{H_2}O\\
b)\\
nC{O_2} = \frac{{11,2}}{{22,4}} = 0,5\,mol\\
n{H_2}O = \frac{9}{{18}} = 0,5\,mol\\
mC + mH = 0,5 \times 12 + 1 \times 1 = 7g\\
nC:nH = 0,5:1 = 1:2\\
= > CTDGN:C{H_2}\\
VB = \frac{7}{{1,25}} = 5,6l\\
MA = \frac{7}{{\frac{{5,6}}{{22,4}}}} = 28g/mol\\
14n = 28 = > n = 2\\
= > CTPTA:{C_2}{H_4}\\
c)\\
nC{O_2} = \frac{{33,85}}{{44}} = 0,77\,mol\\
n{H_2}O = \frac{{6,94}}{{18}} = 0,38\,mol\\
mC + mH = 0,77 \times 12 + 0,38 \times 2 = 10g\\
nC:nH = 0,77:0,77 = 1:1\\
= > CTDGN:CH\\
MA = 2,69 \times 29 = 78\\
13n = 78 = > n = 6\\
= > CTPTA:{C_6}{H_6}
\end{array}\)
