Giải thích các bước giải:
\[\begin{array}{l}
a,\\
{\log _{\sqrt 6 }}3.{\log _3}36 = 2.{\log _6}3.2.{\log _3}6 = 4\frac{{{{\log }_6}3}}{{{{\log }_6}3}} = 4\\
b,\\
{\log _{\sqrt 3 }}8.{\log _4}81 = 2{\log _3}{2^3}.\frac{1}{2}{\log _2}{3^4} = 3{\log _3}2.4{\log _2}3 = 12\\
c,\\
{\log _2}\sqrt {\frac{1}{5}} .{\log _{25}}\sqrt[3]{2} = - \frac{1}{2}.{\log _2}5.\frac{1}{3}{\log _{{5^2}}}2 = \frac{{ - 1}}{6}{\log _2}5.\frac{1}{2}{\log _5}2 = \frac{{ - 1}}{{12}}
\end{array}\]
