$B\dfrac{-1,2:\left ( 1\dfrac{3}{5}.1,25 \right )}{0,64}+\dfrac{\left ( 1,08-\dfrac{2}{25} \right ):\dfrac{4}{7}}{\left ( 5\dfrac{5}{9}-\dfrac{9}{4} \right ).\dfrac{36}{17}}+0,6.0,5:\dfrac{2}{5}\\B=\dfrac{-1,2:\left ( \dfrac{8}{5}.\dfrac{5}{4} \right )}{\dfrac{16}{25}}+\dfrac{\left ( \dfrac{27}{25}-\dfrac{2}{25} \right ):\dfrac{4}{7}}{\left ( \dfrac{50}{9}-\dfrac{9}{4} \right ).\dfrac{36}{17}}\\B=\dfrac{-1,2:2}{\dfrac{16}{25}}+\dfrac{1:\dfrac{4}{7}}{\dfrac{119}{36}.\dfrac{36}{17}}+3.\dfrac{1}{2}.\dfrac{1}{2}\\B=\dfrac{-0,6}{\dfrac{16}{25}}+\dfrac{\dfrac{7}{4}}{7}+\dfrac{3}{4}\\B=\dfrac{-\dfrac{3}{5}}{\dfrac{16}{25}}+\dfrac{1}{4}+\dfrac{3}{4}\\B=-\dfrac{\dfrac{3}{5}}{\dfrac{16}{25}}+\dfrac{1}{4}+\dfrac{3}{4}\\B=-\dfrac{15}{16}+\dfrac{1}{4}+\dfrac{3}{4}=\dfrac{1}{16}\\C=\dfrac{\dfrac{-11}{2}+\dfrac{\dfrac{-5}{3}}{1-\dfrac{4}{3}}}{\dfrac{3}{5}-\dfrac{\dfrac{-2}{5}}{\dfrac{4}{5}-\dfrac{2}{3}}}\\C=\dfrac{\dfrac{-11}{2}+\dfrac{\dfrac{-5}{3}}{-\dfrac{1}{3}}}{\dfrac{3}{5}-\dfrac{\dfrac{-2}{5}}{\dfrac{2}{15}}}\\C=\dfrac{\dfrac{-11}{2}+\dfrac{-5}{-1}}{\dfrac{3}{5}+\dfrac{\dfrac{2}{5}}{\dfrac{2}{15}}}\\C=\dfrac{\dfrac{-11}{2}+5}{\dfrac{3}{5}+3}\\C=\dfrac{-\dfrac{1}{2}}{\dfrac{18}{5}}\\C=-\dfrac{5}{36}$
