Câu 1:
a) PTHH: Zn+2HCl → ZnCl2+H2 (1)
ZnO+2HCl → ZnCl2+H2O (2)
b) nH2=0,448 : 22,4=0,02 (mol)
Theo PTHH (1): nZn=nH2=0,02 (mol)
mZn=0,02.65=1,3 (g)
%Zn=(1,3/5,6).100%=23,21%
%ZnO=100-23,21=76,79%
Câu 2:
a) PTHH: Fe+H2SO4 → FeSO4+H2
b) nH2=0,224 : 22,4=0,01 (mol)
Theo PTHH: nFe=nH2=0,01 (mol)
mFe=0,01.56=0,56 (g)
%Fe=(0,56/10).100%=5,6%
%Cu=100-5,6=94,4%