Giải thích các bước giải:
\(\begin{array}{l}
a)Fe + C{\rm{uS}}{O_4} \to FeS{O_4} + Cu\\
{n_{Fe}} = 0,035mol\\
{m_{{\rm{ddCuS}}{O_4}}} = 100 \times 1,12 = 112g\\
\to {m_{{\rm{CuS}}{O_4}}} = \dfrac{{112 \times 10\% }}{{100\% }} = 11,2g\\
\to {n_{{\rm{CuS}}{O_4}}} = 0,07mol\\
\to {n_{{\rm{CuS}}{O_4}}} > {n_{Fe}} \to {n_{{\rm{CuS}}{O_4}}}dư\\
\to {n_{{\rm{CuS}}{O_4}(pt)}} = {n_{Fe}} = 0,035mol\\
\to {n_{{\rm{CuS}}{O_4}}}dư = 0,035mol\\
b)\\
{n_{FeS{O_4}}} = {n_{Fe}} = 0,035mol\\
\to C{M_{FeS{O_4}}} = C{M_{{\rm{CuS}}{O_4}}}dư = \dfrac{{0,035}}{{0,1}} = 0,35M\\
c)\\
{m_{FeS{O_4}}} = 5,32g\\
{m_{{\rm{CuS}}{O_4}}}dư = 5,6g
\end{array}\)