Đáp án:
Canxi
Giải thích các bước giải:
\(\begin{array}{l}
T{N_1}:\\
A + 2HCl \to AC{l_2} + {H_2}\\
{n_{{H_2}}} = \dfrac{{6,72}}{{22,4}} = 0,3\,mol\\
{n_A} = {n_{{H_2}}} = 0,3\,mol\\
\Rightarrow {M_A} = \dfrac{{15}}{{0,3}} = 50\,g/mol \Rightarrow {M_M} < 50g/mol(1)\\
T{N_2}:\\
M + 2HCl \to MC{l_2} + {H_2}\\
{n_M} < \dfrac{4}{{22,4}} \Rightarrow {n_M} < \dfrac{5}{{28}}\,mol\\
\Rightarrow {M_M} > \dfrac{6}{{\dfrac{5}{{28}}}} \Rightarrow {M_M} > 33,6\,g/mol(2)\\
(1),(2) \Rightarrow {M_M} = 40\,g/mol \Rightarrow M:Can\,xi(Ca)
\end{array}\)