Đáp án:
\(\begin{array}{l}
a)\\
hh:Natri(Na),Kali(K)\\
b)\\
{C_M}NaOH = 2M\\
{C_M}KOH = 1M
\end{array}\)
Giải thích các bước giải:
\(\begin{array}{l}
a)\\
2R + 2{H_2}O \to 2ROH + {H_2}\\
{n_{{H_2}}} = \dfrac{{6,72}}{{22,4}} = 0,3\,mol\\
{n_R} = 2{n_{{H_2}}} = 0,6\,mol\\
{M_R} = \dfrac{{17}}{{0,6}} = 28,333(g/mol)\\
\Rightarrow hh:Natri(Na),Kali(K)\\
b)\\
2Na + 2{H_2}O \to 2NaOH + {H_2}\\
2K + 2{H_2}O \to 2KOH + {H_2}\\
hh:Na(a\,mol),K(b\,mol)\\
a + b = 0,6\\
23a + 39b = 17\\
\Rightarrow a = 0,4;b = 0,2\\
{n_{NaOH}} = {n_{Na}} = 0,4\,mol\\
{n_{KOH}} = {n_K} = 0,2\,mol\\
{C_M}NaOH = \dfrac{{0,4}}{{0,2}} = 2M\\
{C_M}KOH = \dfrac{{0,2}}{{0,2}} = 1M
\end{array}\)