$n_{H_2SO_4}=0,2.2=0,4(mol)$
$2KOH+H_2SO_4\to K_2SO_4+2H_2O$
$\Rightarrow n_{KOH}=0,4.2=0,8(mol)$
$\Rightarrow C_{M_{KOH}}=\dfrac{0,8}{0,2}=4M$
$ZnCl_2+2KOH\to Zn(OH)_2+2KCl$
$\Rightarrow n_{Zn(OH)_2}=0,8:2=0,4(mol)$
$m_{Zn(OH)_2\downarrow}=0,4.99=39,6g$