Đáp án:
\(\begin{array}{l}
b)\\
{m_{Zn}} = 13g\\
{m_{Cu}} = 8g\\
c)\\
\% {m_{Zn}} = 61,9\% \\
\% {m_{Cu}} = 38,1\%
\end{array}\)
Giải thích các bước giải:
\(\begin{array}{l}
a)\\
Zn + {H_2}S{O_4} \to ZnS{O_4} + {H_2}\\
b)\\
{n_{{H_2}}} = \dfrac{{4,48}}{{22,4}} = 0,2\,mol\\
{n_{Zn}} = {n_{{H_2}}} = 0,2\,mol\\
{m_{Zn}} = 0,2 \times 65 = 13g\\
{m_{Cu}} = 21 - 13 = 8g\\
c)\\
\% {m_{Zn}} = \dfrac{{13}}{{21}} \times 100\% = 61,9\% \\
\% {m_{Cu}} = 100 - 61,9 = 38,1\%
\end{array}\)