a,2Na + 2H2O ----> 2NaOH + H2
nNa=5,57:23=557/2300(mol)
b,Theo PTHH: nNaOH=nNa=557/2300(mol)
=>m NaOH=557/2300.40=9,7(g)
Theo PTHH:nH2=1/2.n Na=557/4600(mol)
=>V H2=557/4600.2,4=2,71(l)
c,2H2 + O2 --to--> 2H2O
Theo PTHH:nO2=1/.nH2=557/9200
=>V O2= 557/9200.22,4=1.36(l)
=>V kk=1,36.5=6,72(l)
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P/s:nhung cai minh in dam deu thuoc gia tri minh lay xap xi ban nha!