`n_{MnO_2}={69,6}/{87}=0,8(mol)`
`MnO_2+4HCl->MnCl_2+Cl_2+2H_2O`
`n_{Cl_2}=n_{MnO_2}=0,8(mol)`
`n_{NaOH}=0,5.4=2(mol)`
`Cl_2+2NaOH->NaCl+NaClO+H_2O`
Do `2.0,8<2->NaOH` dư
`n_{NaCl}=n_{NaClO}=0,8(mol)`
`n_{NaOH(du)}=2-0,8.2=0,4(mol)`
`C_{M\ NaCl}=C_{M\ NaClO}={0,8}/{0,5}=1,6M`
`C_{M\ NaOH(du)}={0,4}/{0,5}=0,8M`