Đáp án:
$\begin{array}{l}
A = {\left( {x - 8} \right)^2} - 2018\\
Do:{\left( {x - 8} \right)^2} \ge 0\forall x\\
\Rightarrow {\left( {x - 8} \right)^2} - 2018 \ge - 2018\forall x\\
\Rightarrow A \ge - 2018\\
\Rightarrow GTNN:A = - 2018\,\\
Khi\,và\,chỉ\,khi:x - 2018 = 0 \Rightarrow x = 2018\\
B = - {\left( {x + 5} \right)^2} + 9\\
Do: - {\left( {x + 5} \right)^2} \le 0\forall x\\
\Rightarrow - {\left( {x + 5} \right)^2} + 9 \le 9\forall x\\
\Rightarrow B \le 9\\
\Rightarrow GTLN:B = 9 \Leftrightarrow x + 5 = 0 \Rightarrow x = - 5
\end{array}$