Em tham khảo nha :
\(\begin{array}{l}
CuO + {H_2}S{O_4} \to CuS{O_4} + {H_2}O\\
{n_{CuS{O_4}}} = \dfrac{{32}}{{160}} = 0,2mol\\
{m_{{H_2}S{O_4}}} = \dfrac{{245 \times 30}}{{100}} = 73,5g\\
{n_{CuO}} = {n_{CuS{O_4}}} = 0,2mol\\
{m_{CuO}} = 0,2 \times 80 = 16g\\
{n_{{H_2}S{O_4}}} = {n_{CuS{O_4}}} = 0,2mol\\
{m_{{H_2}S{O_4}pu}} = 0,2 \times 98 = 19,6g\\
{m_{{H_2}S{O_4}d}} = 73,5 - 19,6 = 53,9g\\
C{\% _{CuS{O_4}}} = \dfrac{{32}}{{16 + 245}} \times 100\% = 12,26\% \\
C{\% _{{H_2}S{O_4}}} = \dfrac{{53,9}}{{16 + 245}} \times 100\% = 20,65\%
\end{array}\)