$\vec{n_d}= (4;3)\Rightarrow \vec{u_d}= (-3;4)$
$\vec{n_d'}= (1;7)\Rightarrow \vec{u_d'}= (-7;1)$
$\Rightarrow \vec{u_d}.\vec{u_d'}= (-3).(-7)+4=25$
$|\vec{u_d}|= \sqrt{3^2+4^2}=5$
$|\vec{u_d'}|=\sqrt{7^2+1^2}=5\sqrt2$
$\Rightarrow cos(d, d')=\dfrac{25}{5.5\sqrt2}=\dfrac{\sqrt{2}}{2}$
$\Rightarrow (d,d')=45^o+ k360^o$ hoặc $-45^o+ k360^o$
Vậy góc quay là $\pm 45^o+ k360^o$