Giải phương trình \(3{{x}^{4}}-2{{x}^{2}}-1=0 \).
A.\(x=1\)
B.\({{x}_{1}}=1\,\,;\,\,\,{{x}_{2}}=-1\,\,;\,\,\,{{x}_{3}}=0.\)
C.\({{x}_{1}}=-1\,\,;\,\,\,{{x}_{2}}=1\)
D.\({{x}_{1}}=1\,\,;\,\,\,{{x}_{2}}=-1\,\,;\,\,\,{{x}_{3}}=\frac{1}{\sqrt{3}}\,\,;\,\,\,{{x}_{4}}=\frac{-1}{\sqrt{3}}\)