Giải thích các bước giải:
a) `ΔBIC` có: `\hat{BIC} + \hat{IBC} + \hat{ICB} = 180^o`
`⇒ \hat{BIC} + 1/2 \hat{ABC} + 1/2 \hat{ACB} = 180^o`
`⇒ \hat{BIC} + 1/2 (\hat{ABC} + \hat{ACB}) = 180^o`
`⇒ \hat{BIC} + 1/2 (180^o - \hatBAC}) = 180^o`
`⇒ \hat{BIC} + 90^o - \hat{BAC}/2 = 180^o`
`⇒ \hat{BIC} = 180^o - 90^o + \hat{BAC}/2`
`⇒ \hat{BIC} = 90^o + \hat{BAC}/2 (đpcm)`
b)