Cho \(\int\limits_{0}^{1}{\frac{\left( {{x}^{2}}+x \right){{\text{e}}^{x}}}{x+{{\text{e}}^{-x}}}\text{d}x}=a.\text{e}+b\ln \left( \text{e}+c \right)\) với \(a\), \(b\), \(c\in \mathbb{Z}\). Tính \(P=a+2b-c\).
A.\(P=-1\)
B. \(P=1\)
C. \(P=-2\)
D. \(P=0\)