Đáp án đúng:
Giải chi tiết:\(\begin{gathered} (1)\,2N{H_3}\xrightarrow{{{{500}^0}C}}\,{N_2} \uparrow + 3{H_2} \uparrow \hfill \\ \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,X\,\,\,\,\,\,\,\,\,\,\,Y \hfill \\ (2)\,{N_2} + 3{H_2}\underset{{}}{\overset{{{{400}^0}C,\,Fe}}{\longleftrightarrow}}2N{H_3} \hfill \\ \,\,\,\,\,\,\,X\,\,\,\,\,\,\,\,Y \hfill \\ (3)\,{N_2} + \,Al\xrightarrow{{}}2AlN \hfill \\ \,\,\,\,\,\,\,X\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{X_1} \hfill \\ (4)\,2{H_2} + {O_2}\xrightarrow{{}}\,2{H_2}O \hfill \\ \,\,\,\,\,\,\,\,Y\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{Y_1} \hfill \\ (5)\,C{l_2} + \,{H_2}O\underset{{}}{\overset{{}}{\longleftrightarrow}}HCl + HClO \hfill \\ \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{Y_1}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{Y_2} \hfill \\ (6)\,AlN\, + 3{H_2}O\xrightarrow{{}}N{H_3} \uparrow \, + Al{(OH)_3} \downarrow \hfill \\ \,\,\,\,\,\,\,\,{X_1} \hfill \\ (7)\,N{H_3} + HCl\xrightarrow{{}}\,N{H_4}Cl \hfill \\ \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{Y_2} \hfill \\ (8)\,2N{H_3}\, + {H_2}S{O_4}\xrightarrow{{}}\,{(N{H_4})_2}S{O_4} \hfill \\ \,\,\,\,\,\,\,\,\,\,X\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{X_2} \hfill \\ (9)\,AlN\, + 3{H_2}O\xrightarrow{{}}N{H_3} \uparrow + \,Al{(OH)_3} \downarrow \hfill \\ (10)\,N{H_3} + HCl\xrightarrow{{}}\,N{H_4}Cl \hfill \\ \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{Y_2} \hfill \\ \end{gathered} \)
