Đáp án:
\(\begin{array}{l}
\% {m_{C{H_4}}} = 12,9\% \\
\% {m_{{C_2}{H_4}}} = 45,2\% \\
\% {m_{{C_2}{H_2}}} = 41,9\%
\end{array}\)
Giải thích các bước giải:
\(\begin{array}{l}
{C_2}{H_4} + B{r_2} \to {C_2}{H_4}B{r_2}\\
{C_2}{H_2} + 2B{r_2} \to {C_2}{H_2}B{r_4}\\
C{H_4} + 2{O_2} \xrightarrow{t^0} C{O_2} + 2{H_2}O\\
{n_{hh}} = \dfrac{{5,6}}{{22,4}} = 0,25\,mol\\
{n_{C{O_2}}} = \dfrac{{2,2}}{{44}} = 0,05\,mol\\
hh:C{H_4}(a\,mol),{C_2}{H_4}(b\,mol),{C_2}{H_2}(c\,mol)\\
\left\{ \begin{array}{l}
a = 0,05\\
28b + 26c = 5,4\\
a + b + c = 0,25
\end{array} \right.\\
\Rightarrow a = 0,05;b = c = 0,1\\
\% {m_{C{H_4}}} = \dfrac{{0,05 \times 16}}{{0,05 \times 16 + 0,1 \times 28 + 0,1 \times 26}} \times 100\% = 12,9\% \\
\% {m_{{C_2}{H_4}}} = \dfrac{{0,1 \times 28}}{{0,05 \times 16 + 0,1 \times 28 + 0,1 \times 26}} \times 100\% = 45,2\% \\
\% {m_{{C_2}{H_2}}} = 100 - 12,9 - 45,2 = 41,9\%
\end{array}\)
