m tăng= mCl2 phản ứng= 4,26g
Theo lí thuyết:
nAl= 0,0615 mol
2Al+ 3Cl2 -> 2AlCl3
=> nCl2 phản ứng= 0,09225 mol
=> mCl2 phản ứng= 6,54975g
=> H= $\frac{4,26.100}{6,54975}$= 65%
$Δm=m_{Cl_2}$ phản ứng $=4,26(g)$$n_{Al}=$ $\dfrac{1,6615}{27}=0,0615 (mol)$
PTHH: 2Al + 3Cl2 $→$ 2AlCl3
$→$ $n_{Cl_2}$ phản ứng $=1,5n_{Al}=1,5\times 0,0615 = 0,09225 (mol)$
$→H=$ $\dfrac{4,26}{0,09225\times 71}\times 100\%=65\%$
giải phương trình (x-1)^3 + (x-2)^3 = (2x-1)^3 giúp mị với các tình yêu mị nghĩ đặt x-1=a nhưng mị vẫn ko giải ra đc T^T
hai đoạn dây dẫn thẳng dài đặt song song với nhau trong không khí cách nhau 1 khoảng 20cm. Dòng điện qua dây thứ nhất có cường độ 5A. Trên mỗi mét chiều dài của dây dẫn chịu tác dụng một lực F=2X10^-5 N
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Chế nào vẽ giúp tui, một bạn Bảo Bình nữ Đẹp nha!!!!!
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