Đáp án:
a) 7,8g
b) 26
Giải thích các bước giải:
\(\begin{array}{l}
a)\\
nC{O_2} = \dfrac{{12,32}}{{22,4}} = 0,55\,mol\\
n{H_2}O = \dfrac{{10,8}}{{18}} = 0,6\,mol\\
BTNT\,O\\
2n{O_2} = 2nC{O_2} + n{H_2}O \Rightarrow n{O_2} = 0,85\,mol\\
BTKL\\
mX + m{O_2} = mC{O_2} + m{H_2}O \Rightarrow mX = 7,8g\\
b)\\
nX = \dfrac{{3,36}}{{22,4}} = 0,15\,mol \Rightarrow MX = \dfrac{{7,8}}{{0,15}} = 52g/mol\\
dX/{H_2} = \dfrac{{52}}{2} = 26
\end{array}\)