Đáp án đúng: D
Ankan.
$\begin{array}{l}{{n}_{C{{O}_{2}}}}\,=\,{{n}_{CaC{{O}_{3}}\,\downarrow }}\,=\,0,65\,mol\\({{m}_{\text{dd}\,trc}}\,-\,{{m}_{\text{dd}\,sau}})\,=\,22\,=\,{{m}_{CaC{{O}_{3}}}}\,-\,{{m}_{C{{O}_{2}}}}\,-\,{{m}_{{{H}_{2}}O}}\,=\,0,65.(100\,-\,44)\,-\,{{m}_{{{H}_{2}}O}}\\\Rightarrow \,{{m}_{{{H}_{2}}O}}\,=\,14,4\,gam\,\Rightarrow \,{{n}_{{{H}_{2}}O}}\,=\,0,8\,mol\,>\,{{n}_{C{{O}_{2}}}}\,\Rightarrow \,ankan\end{array}$