Đáp án + Giải thích các bước giải:
`e)`
`-2|1/2x-1/3| + 3/2 = 1/4`
`\to -2|1/2x-1/3| = 1/4 - 3/2`
`\to -2|1/2x-1/3| = -5/4`
`\to |1/2x-1/3| = -5/4 : (-2)`
`\to |1/2x-1/3| = 5/8`
TH1 : `1/2x - 1/3 = 5/8 \to 1/2x = 23/24 \to x = 23/12`
TH2 : `1/2x - 1/3 = -5/8 \to 1/2x = -7/24 \to x = -7/12`
Vậy `x \in {-7/12,23/12}`
`f)`
`1/2x + 4/5 = 14/24x - 3/2`
`\to 30/60x + 48/60 = 35/60x - 90/60`
`\to 30x + 48 = 35x - 90`
`\to 30x - 35x = -90 - 48`
`\to -5x = -138`
`\to x = 138/5`
Vậy `x \in {138/5}`
