A.B.C.D.
A.\(\dfrac{{3\sin x - \sin 3x}}{{12}} + C\)B.\(\dfrac{{3\cos x - \cos 3x}}{{12}} + C\)C.\({\sin ^3}x + C\)D.\(\sin x{\cos ^2}x + C\)
A.\(\int {{{\cos }^2}2xdx} = \dfrac{x}{2} + \dfrac{1}{8}\sin 4x + C\)B.\(\int {{{\sin }^2}2xdx} = \dfrac{x}{2} - \dfrac{1}{8}\sin 4x + C\)C.\(\int {\cos 4xdx} = \dfrac{1}{4}\sin 4x + C\)D.\(\int {{{\cos }^2}2xdx} = - {\cos ^2}2x + C\)
A.\(\int {\cos 3x\cos xdx} = \dfrac{1}{2}\left( {\dfrac{1}{4}\sin 4x + \dfrac{1}{2}\sin 2x} \right) + C\)B.\(\int {\sin 3x\cos xdx} = \dfrac{{ - 1}}{2}\left( {\dfrac{1}{4}\cos 4x + \dfrac{1}{2}\sin 2x} \right) + C\)C.\(\int {\sin 3x\cos xdx} = \dfrac{{ - 1}}{2}\left( {\dfrac{1}{4}\cos 4x + \dfrac{1}{2}\cos 2x} \right) + C\)D.\(\int {\sin x\cos xdx} = \dfrac{{ - \cos 2x}}{4} + C\)
A.\(\dfrac{1}{3}{\sin ^3}x - \dfrac{1}{5}{\sin ^5}x + C\)B.\( - \dfrac{1}{3}{\sin ^3}x + \dfrac{1}{5}{\sin ^5}x + C\)C.\({\sin ^3}x - {\sin ^5}x + C\)D.Đáp án khác
A.\(\cos x + {\sin ^2}x - \dfrac{{{{\sin }^3}x}}{3} - \dfrac{{{{\cos }^4}x}}{4} + C\)B.\(\sin x + \dfrac{{{{\sin }^2}x}}{2} - \dfrac{{{{\sin }^3}x}}{3} - \dfrac{{{{\cos }^4}x}}{4} + C\)C.\( - \dfrac{{{{\sin }^4}x}}{4} - \dfrac{{{{\sin }^3}x}}{3} + \dfrac{{{{\cos }^2}x}}{2} + \sin x + C\)D.\( - \dfrac{{{{\sin }^4}x}}{4} - \dfrac{{{{\sin }^3}x}}{3} + \dfrac{{{{\cos }^2}x}}{2} - \sin x + C\)
A.\(2x - \dfrac{1}{{10}}\sin 10x - \dfrac{1}{5}\cos 10x\)B.\(2x - \dfrac{1}{{10}}\sin 10x - \dfrac{2}{5}\cos 10x\)C.\(2x - \dfrac{1}{5}\sin 10x - \dfrac{1}{{10}}\cos 10x\)D.\(2x - \dfrac{3}{{10}}\sin 10x - \dfrac{2}{5}\cos 10x\)
A.\( - \dfrac{1}{6}\cos 6x - \dfrac{1}{2}\cos 2x + 6\)B.\( - \dfrac{1}{6}\cos 6x - \dfrac{3}{2}\cos 2x + 6\)C.\( - \dfrac{1}{6}\cos 6x - \dfrac{{\sqrt 3 }}{2}\cos 2x + 8\)D.\( - \dfrac{1}{6}\cos 6x - \dfrac{5}{2}\sin 2x + 8\)
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