Find a mistake in the four underlined parts of the sentence and correct it:
We went on a cruise down a Nile and saw the Pyramids.
A. went on
B. a cruise
C. a Nile
D. the Pyramids

Find a mistake in the four underlined parts of the sentence and correct it:
At least two players must touch the ball after a free throw before a goal can score.
A. At least
B. must touch
C. before
D. can score

Find a mistake in the four underlined parts of the sentence and correct it:
Do you ever feel that life is not being fair to you because you cannot seem to get the job where you want or that really suits you?
A. ever
B. that
C. because
D. where

Find a mistake in the four underlined parts of the sentence and correct it:
I suppose that’s the house where we’ll have to stay in there.
A. that’s
B. where
C. have to
D. in there

Find a mistake in the four underlined parts of the sentence and correct it:
It mustn't have been Mr.Andrew you saw because he's in Liverpool.
A. mustn't
B. you saw
C. because
D. in

Find a mistake in the four underlined parts of the sentence and correct it:
This could have done much more easily by a machine.
A. have
B. much
C. easily
D. machine

Find a mistake in the four underlined parts of the sentence and correct it:
I’ve turned on so much weight recently that I’ll have to go on a diet.
A. turned
B. much
C. recently
D. go on

Các điểm gián đoạn của hàm số:
A. x = -2.
B. Không có.
C. x < -2.
D. x > -2.

Kết quả của giới hạn $\displaystyle \lim \frac{{{3}^{n}}-1}{{{2}^{n}}-{{2.3}^{n}}+1}$ bằng 
A. $\displaystyle -1.$ 
B. $\displaystyle -\frac{1}{2}.$ 
C. $\frac{1}{2}.$ 
D. $\displaystyle \frac{3}{2}.$

Cho hình hộp $\displaystyle ABCD.{{A}_{1}}{{B}_{1}}{{C}_{1}}{{D}_{1}}$. Chọn khẳng định đúng?
A. $\overrightarrow{BD},\overrightarrow{B{{D}_{1}}},\overrightarrow{B{{C}_{1}}}$ đồng phẳng. 
B. $\overrightarrow{C{{D}_{1}}},\overrightarrow{AD},\overrightarrow{{{A}_{1}}{{B}_{1}}}$ đồng phẳng.
C. $\overrightarrow{C{{D}_{1}}},\overrightarrow{AD},\overrightarrow{{{A}_{1}}B}$ đồng phẳng.
D. $\overrightarrow{AB},\overrightarrow{AD},\overrightarrow{{{C}_{1}}A}$ đồng phẳng.