A.\(1 \le m \le 3\)
B.\(1 < m < 3\)
C.\(\left[ \begin{array}{l}m < 1\\m > 3\end{array} \right.\)
D.\(\left[ \begin{array}{l}m \le 1\\m \ge 3\end{array} \right.\)

A.\(m <  - \dfrac{3}{2}\)
B.\(m >  - \dfrac{3}{2}\) và \(m \ne 0\)
C.\( - \dfrac{3}{2} < m < 0\)
D.\(m >  - \dfrac{3}{2}\)

A.\(\dfrac{{ - 6 - 2\sqrt {19} }}{3} < m < \dfrac{{ - 6 + 2\sqrt {19} }}{3}\)
B.\(\dfrac{{ - 6 - 2\sqrt {19} }}{5} < m < \dfrac{{ - 6 + 2\sqrt {19} }}{5}\)
C.\(\dfrac{{ - 6 - 19\sqrt 2 }}{5} < m < \dfrac{{ - 6 + 19\sqrt 2 }}{5}\)
D.\(\dfrac{{ - 6 - 19\sqrt 2 }}{3} < m < \dfrac{{ - 6 + 19\sqrt 2 }}{3}\)

A.\(3\)
B.\(4\)
C.\(5\)
D.\(6\)

A.\(64\)
B.\(65\)
C.\( - 7\)
D.\( - 9\)

A.
B.
C.
D.

A.\(f\left( x \right) > g\left( x \right)\)
B.\(\left\{ \begin{array}{l}f\left( x \right) > g\left( x \right)\\f\left( x \right) >  - g\left( x \right)\end{array} \right.\)
C.\(\left[ \begin{array}{l}f\left( x \right) > g\left( x \right)\\f\left( x \right) <  - g\left( x \right)\end{array} \right.\)
D.\(\left[ \begin{array}{l}f\left( x \right) > g\left( x \right)\\f\left( x \right) >  - g\left( x \right)\end{array} \right.\)

A.\(\left\{ \begin{array}{l}f\left( x \right) \le g\left( x \right)\\g\left( x \right) \ge 0\end{array} \right.\)
B.\(\left\{ \begin{array}{l}f\left( x \right) \le g\left( x \right)\\f\left( x \right) \le  - g\left( x \right)\end{array} \right.\)
C.\(\left[ \begin{array}{l}f\left( x \right) \le g\left( x \right)\\f\left( x \right) \ge  - g\left( x \right)\end{array} \right.\)
D.\(\left\{ \begin{array}{l}f\left( x \right) \ge  - g\left( x \right)\\f\left( x \right) \le g\left( x \right)\end{array} \right.\)

A.\(\emptyset \) 
B.\(\left( { - \infty ;\,\,0} \right)\)
C.\(\left( {0;\,\,4} \right)\)
D.\(\left( { - \infty ;\,\,0} \right) \cup \left( {4;\,\, + \infty } \right)\)

A.\(x \in \left( { - \infty ;\,\, - \dfrac{1}{2}} \right)\) 
B.\(x \in \left( {1;\,\, + \infty } \right)\)
C.\(x \in \left( {3;\,\, + \infty } \right)\) 
D.\(x \in \left( { - \infty ;\,\, - \dfrac{1}{2}} \right) \cup \left( {1;\,\,\dfrac{3}{2}} \right) \cup \left( {1;\,\,\dfrac{3}{2}} \right)\)