Đáp án:
Tính
`a, (4/25)^6 : (2/5)^8`
`= ((2/5)^2)^6 : (2/5)^8`
`= (2/5)^12 : (2/5)^8`
`= (2/5)^(12-8)`
`= (2/5)^4`
`= 16/625`
`b, (1/9)^25 : (1/3)^30`
`= ((1/3)^2)^25 : (1/3)^30`
`= (1/3)^50 : (1/3)^30`
`= (1/3)^(50-30)`
`= (1/3)^20`
`= 1/3^20`
`c, (-0,125)^5 . (-8)^5`
`= [(-0,125) . (-8)]^5`
`= 1^5`
`= 1`
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