Đáp án:
$\begin{array}{l}
Dkxd:x \ne - 1\\
\dfrac{{{x^2} - 1}}{{2x + 2}} > 0\\
\Rightarrow \dfrac{{\left( {x - 1} \right)\left( {x + 1} \right)}}{{2\left( {x + 1} \right)}} > 0\\
\Rightarrow \dfrac{{x - 1}}{2} > 0\\
\Rightarrow x - 1 > 0\\
\Rightarrow x > 1\\
Vậy\,x > 1
\end{array}$