Đáp án:
A) x=1
B) x>6
Giải thích các bước giải:
\(\begin{array}{l}
A)\, \Leftrightarrow 6x - 6 = 0 \Leftrightarrow x = 1\\
B)\, \Leftrightarrow \left\{ \begin{array}{l}
x > 5\\
{\log _3}\left[ {\left( {x - 3} \right)\left( {x - 5} \right)} \right] > 1
\end{array} \right.\\
\Leftrightarrow \left\{ \begin{array}{l}
x > 5\\
{x^2} - 8x + 15 > 3
\end{array} \right. \Leftrightarrow \left\{ \begin{array}{l}
x > 5\\
{x^2} - 8x + 12 > 0
\end{array} \right.\\
\Leftrightarrow \left\{ \begin{array}{l}
x > 5\\
\left[ \begin{array}{l}
x > 6\\
x < 2
\end{array} \right.
\end{array} \right. \Rightarrow x > 6
\end{array}\)
