Đáp án:
b) \(\left[ \begin{array}{l}
x = 4\\
x = 1
\end{array} \right.\)
Giải thích các bước giải:
\(\begin{array}{l}
C1:\\
a)DK:2x - 1 \ge 0 \to x \ge \dfrac{1}{2}\\
\to TXD:D = \left[ {\dfrac{1}{2}; + \infty } \right)\\
b)DK:x \ge \dfrac{3}{7}\\
\sqrt {7x - 3} = x + 1\\
\to 7x - 3 = {x^2} + 2x + 1\\
\to {x^2} - 5x + 4 = 0\\
\to \left( {x - 4} \right)\left( {x - 1} \right) = 0\\
\to \left[ \begin{array}{l}
x = 4\\
x = 1
\end{array} \right.\left( {TM} \right)
\end{array}\)
