`\text{Harry}`
`75/x+75/(x+5)=11/2`
`<=>(75(x+5))/(x(x+5))+75x/(x(x+5))=11/2`
`<=>(75(x+375))/(x(x+5))+75x/(x(x+5))=11/2`
`<=>11(x^2+5x)=2(150x+375)`
`<=>11x^2+55x=300x+750)`
`<=>11x^2-245x-750=0`
`Δ=(-245)^2-4xx11xx(-750)`
`Δ=60025+33000`
`Δ=93025`
`=>\sqrt{Δ}=305`
`Δ>0:\text{PT có 2 nghiệm phân biệt}`
`x_1=(245+305)/22=25,x_2=(245-305)/22=(-30)/11`