Giải phương trình \(1 + \sin 3x = \sin x + \cos 2x\).
A.\(\left[ \begin{array}{l}x = k\pi \\x =- \dfrac{\pi }{2} + k\pi \\x = \dfrac{\pi }{6} + k2\pi \\x = \dfrac{{7\pi }}{6} + k2\pi \end{array} \right.\)
B.\(\left[ \begin{array}{l}x = k\pi \\x = \dfrac{\pi }{2} + k2\pi \\x =  \dfrac{\pi }{6} + k2\pi \\x = -\dfrac{{7\pi }}{6} + k2\pi \end{array} \right.\)
C.\(\left[ \begin{array}{l}x = k\pi \\x = -\dfrac{\pi }{2} + k2\pi \\x = \dfrac{\pi }{6} + k2\pi \\x = \dfrac{{7\pi }}{6} + k2\pi \end{array} \right.\)
D.\(\left[ \begin{array}{l}x = k\pi \\x = \dfrac{\pi }{2} + k2\pi \\x = - \dfrac{\pi }{6} + k2\pi \\x = \dfrac{{7\pi }}{6} + k2\pi \end{array} \right.\)

Các câu hỏi liên quan