Giải phương trình: \({x^2} + 6x + 5 = \sqrt {x + 7} \).
A.\(x = \frac{{ - 5 \pm \sqrt {17} }}{2};x = \frac{{ - 7 \pm \sqrt {13} }}{2}\)
B.\(x = \frac{{ - 5 - \sqrt {17} }}{2};x = \frac{{ - 7 + \sqrt {13} }}{2}\)
C.\(x = \frac{{ - 5 - \sqrt {17} }}{2};x = \frac{{ - 7 - \sqrt {13} }}{2}\)
D.\(x = \frac{{ - 5 + \sqrt {17} }}{2};x = \frac{{ - 7 - \sqrt {13} }}{2}\)
A.\(x = \frac{{ - 5 \pm \sqrt {17} }}{2};x = \frac{{ - 7 \pm \sqrt {13} }}{2}\)
B.\(x = \frac{{ - 5 - \sqrt {17} }}{2};x = \frac{{ - 7 + \sqrt {13} }}{2}\)
C.\(x = \frac{{ - 5 - \sqrt {17} }}{2};x = \frac{{ - 7 - \sqrt {13} }}{2}\)
D.\(x = \frac{{ - 5 + \sqrt {17} }}{2};x = \frac{{ - 7 - \sqrt {13} }}{2}\)
Loga
Hóa Học lớp 12
