Giải phương trình: \(\dfrac{1}{{3x - 1}} + \dfrac{1}{{2x + 4}} = \dfrac{1}{{9x - 2}} + \dfrac{1}{{5 - 4x}}\)
A.\(\left\{ {\dfrac{4}{7};\dfrac{-1}{7}} \right\}\).
B.\(\left\{ {\dfrac{{ - 3}}{5};\dfrac{6}{7};\dfrac{1}{6}} \right\}\).
C.\(\left\{ {\dfrac{{ 2}}{5};\dfrac{1}{7};\dfrac{5}{6}} \right\}\).
D.\(\left\{ {\dfrac{{-2}}{5};\dfrac{1}{6}} \right\}\).
A.\(\left\{ {\dfrac{4}{7};\dfrac{-1}{7}} \right\}\).
B.\(\left\{ {\dfrac{{ - 3}}{5};\dfrac{6}{7};\dfrac{1}{6}} \right\}\).
C.\(\left\{ {\dfrac{{ 2}}{5};\dfrac{1}{7};\dfrac{5}{6}} \right\}\).
D.\(\left\{ {\dfrac{{-2}}{5};\dfrac{1}{6}} \right\}\).
Loga
Hóa Học lớp 12
