Đáp án:
`S={-5/2;3/2}`
Giải thích các bước giải:
`x/3 .(2x+5)=(2x+5).(x-1)`
`↔x/3 .(2x+5)-(2x+5).(x-1)=0`
`↔(2x+5).(x/3-x+1)=0`
`↔(2x+5).((x-3x+3)/3)=0`
`↔` \(\left[ \begin{array}{l}2x+5=0\\3-2x=0\end{array} \right.\)
`↔` \(\left[ \begin{array}{l}x=-\dfrac{5}{2}\\x=\dfrac{3}{2}\end{array} \right.\)
Vậy `S={-5/2;3/2}`