Đáp án:
\(x = \dfrac{{203}}{{19}}\)
Giải thích các bước giải:
\(\begin{array}{l}
w)\dfrac{{2x - \dfrac{{4 - 3x}}{5}}}{{15}} = \dfrac{{3\left( {7x - \dfrac{{x - 3}}{2}} \right) - 15x + 15}}{{15}}\\
\to 2x - \dfrac{{4 - 3x}}{5} = 3\left( {7x - \dfrac{{x - 3}}{2}} \right) - 15x + 15\\
\to \dfrac{{10x - 4 + 3x}}{5} = 3\left( {\dfrac{{14x - x + 3}}{2}} \right) - 15x + 15\\
\to \dfrac{{13x - 4}}{5} = \dfrac{{39x + 9 - 30x + 30}}{2}\\
\to 2\left( {13x - 4} \right) = 5\left( {9x + 39} \right)\\
\to 26x - 8 = 45x + 195\\
\to 19x = 203\\
\to x = \dfrac{{203}}{{19}}
\end{array}\)
