Đáp án:
`\hat{EAK}=48°`
Giải thích các bước giải:
Ta có:
`\qquad \hat{AMH}+\hat{EMH}=180°` (hai góc kề bù)
`=>\hat{AMH}+110°=180°`
`=>\hat{AMH}=70°`
$\\$
`\qquad \hat{AHM}+\hat{MHK}=180°` (hai góc kề bù)
`=>\hat{AHM}+118°=180°`
`=>\hat{AHM}=62°`
$\\$
Xét $∆AMH$ có:
`\qquad \hat{MAH}+\hat{AMH}+\hat{AHM}=180°`
`=>\hat{EAK}+70°+62°=180°`
`=>\hat{EAK}=48°`
Vậy `\hat{EAK}=48°`
