Đáp án:
Giải thích các bước giải:
$g)x^2-1=24$
$x^2=25$
$x=\pm 5$
$h) 27-(2x-1)^2=18$
$(2x-1)^2=9$
\(\left[ \begin{array}{l}2x-1=3\\2x-1=-3\end{array} \right.\)
\(\left[ \begin{array}{l}x=2\\x=-1\end{array} \right.\)
$k)(3x-1)^3+13=2$
$(3x-1)^3=-11$
$3x-1=\sqrt[3]{-11}$
$x=\dfrac{\sqrt[3]{-11}+1}{3}$
$f)12-|x+5|=6$
$|x+5|=6$
\(\left[ \begin{array}{l}x+5=6\\x+5=-6\end{array} \right.\)
\(\left[ \begin{array}{l}x=1\\x=-11\end{array} \right.\)
$m)|2x-3|=|x-3|$
\(\left[ \begin{array}{l}2x-3=x-3\\2x-3=-x+3\end{array} \right.\)
\(\left[ \begin{array}{l}x=0\\3x=6\end{array} \right.\)
\(\left[ \begin{array}{l}x=0\\x=2\end{array} \right.\)
