Đáp án:
\(\begin{array}{l}
10)\,D\\
11)\,B\\
12)\,C\\
13)\,A\\
14)\,D\\
15)\,D\\
16)\,D\\
17)\,B\\
18)\,D\\
19)\,A
\end{array}\)
Giải thích các bước giải:
\(\begin{array}{l}
14)\\
{m_{{H_2}S{O_4}}} = 1 \times 98 = 98g\\
{m_{{\rm{dd}}{H_2}S{O_4}}} = 98 + 18 = 116g\\
{C_\% }{H_2}S{O_4} = \dfrac{{98}}{{116}} \times 100\% = 84,48\% \\
15)\\
{n_{{H_2}S{O_4}}} = \dfrac{{19,6}}{{98}} = 0,2\,mol\\
{C_M}{H_2}S{O_4} = \dfrac{{0,2}}{{0,4}} = 0,5M\\
16)\\
{m_{{H_2}O}} = 450 \times 1 = 450g\\
{m_{{\rm{dd}}CuC{l_2}}} = 50 + 450 = 500g\\
{C_\% }CuC{l_2} = \dfrac{{50}}{{500}} \times 100\% = 10\% \\
18,19)\\
{m_{{\rm{dd}}}} = 20 + 180 = 200g\\
{C_\% } = \dfrac{{20}}{{200}} \times 100\% = 10\%
\end{array}\)
