Đáp án:
$\dfrac{3^{11}.4}{2.13^2-3^{11}}$
Giải thích các bước giải:
$\dfrac{4^6.9^5+6^9.120}{8^4.13^2-6^{11}}$
$=\dfrac{(2^2)^6.(3^2)^5+3^9.2^9.3.2^3.5}{(2^3)^4.13^2-3^{11}.2^{11}}$
$=\dfrac{2^{12}.3^{10}+3^{10}.2^{12}.5}{2^{12}.13^2-3^{11}.2^{11}}$
$=\dfrac{2^{12}.3^{10}.(1+5)}{2^{11}(2.13^2-3^{11})}$
$=\dfrac{2.3^{10}.3.2}{2.13^2-3^{11}}$
$=\dfrac{3^{11}.4}{2.13^2-3^{11}}$
