Đáp án:
`\frac{3^{27}xx15^{30}xx(-4)^{16}}{(-15)^{30}xx8^{11}}:(1-1,2)^2+(1,5-1,2)^2`
`= \frac{3^{27}xx15^{30}xx4^{16}}{15^{30}xx2^{33}}:(-0,2)^2+0,3^2`
`= \frac{3^{27}xx2^{32}}{2^33}:0,2^2+(3/10)^2`
`= \frac{3^{27}}{2}:(1/5)^2+9/100`
`= \frac{3^{27}}{2}:1/25+9/100`
`= \frac{3^{27}}{2}xx25+9/100`
`= \frac{25xx3^{27}}{2}+9/100`