Đáp án:
$\begin{array}{l}
a)A = {x^3} + 12{x^2} + 48x + 64\\
= {\left( {x + 4} \right)^3}\\
= {\left( {6 + 4} \right)^3}\\
= {10^3}\\
= 1000\\
b)B = {x^3} - 6{x^2} + 12x - 8\\
= {\left( {x - 2} \right)^3}\\
= {\left( {22 - 2} \right)^3}\\
= {20^3}\\
= 8000\\
c)C = {x^3} + 9{x^2} + 27x + 27\\
= {\left( {x + 3} \right)^3}\\
= {\left( { - 103 + 3} \right)^3}\\
= {\left( { - 100} \right)^3}\\
= - 1000000\\
d)D = {x^3} - 15{x^2} + 75x - 125\\
= {\left( {x - 5} \right)^3}\\
= {\left( {25 - 5} \right)^3}\\
= {20^3}\\
= 8000
\end{array}$
