Đáp án:
$\begin{array}{l}
\left\{ \begin{array}{l}
\frac{x}{{x - 2}} + \frac{1}{{y + 1}} = 3\\
\frac{4}{{x - 2}} - \frac{3}{{y + 1}} = 1
\end{array} \right. \Rightarrow \left\{ \begin{array}{l}
\frac{{3x}}{{x - 2}} + \frac{3}{{y + 1}} = 9\\
\frac{4}{{x - 2}} - \frac{3}{{y + 1}} = 1
\end{array} \right.\\
\Rightarrow \frac{{3x}}{{x - 2}} + \frac{4}{{x - 2}} = 10\\
\Rightarrow \frac{{3x + 4}}{{x - 2}} = 10\\
\Rightarrow 3x + 4 = 10x - 20\\
\Rightarrow 7x = 24\\
\Rightarrow x = \frac{{24}}{7}\\
Thay\,x = \frac{{24}}{7}\,vào:\frac{x}{{x - 2}} + \frac{1}{{y + 1}} = 3 \Rightarrow y = \frac{2}{5}\\
\left( {x;y} \right) = \left( {\frac{{24}}{7};\frac{2}{3}} \right)
\end{array}$
