\(|2x-3|=\begin{cases}2x-3\,\,nếu\,\,2x-3\ge 0\,\,hay\,\,x\ge \dfrac{3}{2}\\3-2x\,\,nếu\,\,2x-3<0\,\,hay\,\,x<\dfrac{3}{2}\end{cases}\)
TH1: \(x\ge \dfrac{3}{2}\\→2x-3=x-5\\↔2x-x=-5+3\\↔x=-2(KTM)\)
TH2: \(x<\dfrac{3}{2}\\→3-2x=x-5\\↔-2x-x=-5-3\\↔-3x=-8\\↔x=\dfrac{8}{3}(KTM)\)
Vậy pt vô nghiệm \(S=\varnothing\)