Bạn tham khảo :
$N = 1+3^1+3^2+..+3^{99}$
$3N = 3+3^2+3^3+..+3^{100}$
$3N - N =( 3+3^2+3^3+..+3^{100})-( 1+3^1+3^2+..+3^{99})$
$2N = 3^{100} - 1$
$N = 3^{100} - 1:2$
$2^2 +4^2+6^2+..........+20^2$
$= (1.2)^2+(2.2)^2+(3.2)^2+...+(10.2)^2$
$= 1^2.2^2+2^2.2^2+3^2.2^2+...10^2.2^2$
$= (1^2+2^2+ 3^2+...........10^2).2^2$
$= 385.4$
$= 1540$