Đáp án:
Giải thích các bước giải:
$a)$
$sin^4\alpha +cos^4\alpha +2sin^2\alpha.cos^2\alpha$
$=(sin^2\alpha)^2+2sin^2\alpha.cos^2\alpha+(cos^2\alpha)^2$
$=(sin^2\alpha+cos^2\alpha )^2$
$=1$
$b)$
$tan^2\alpha (2cos^2\alpha +sin^2\alpha-1)$
$=tan^2\alpha (1-1+cos^2\alpha)$
$=\dfrac{sin^2\alpha}{cos^2\alpha}.cos^2\alpha$
$=sin^2\alpha$