c) `(7x-3)^{2012}=(3-7x)^{2010}`
⇔`(7x-3)^2=1`
⇔\(\left[ \begin{array}{l}7x-3=1\\7x-3=-1\end{array} \right.\)
⇔\(\left[ \begin{array}{l}7x=4\\7x=2\end{array} \right.\)
⇔\(\left[ \begin{array}{l}x=\dfrac{4}{7}\\x=\dfrac{2}{7}\end{array} \right.\)
Vậy `x=4/7` hoặc `x=2/7`