Đáp án:
\(\begin{array}{l}
a)\\
\% {m_{Zn}} = 35,33\% \\
\% {m_{ZnO}} = 64,67\% \\
b){m_{{\rm{dd}}HCl}} = 60g\\
c){m_{{\rm{dd}}thuđược}} = 69,1g
\end{array}\)
Giải thích các bước giải:
\(\begin{array}{l}
Zn + 2HCl \to ZnC{l_2} + {H_2}\\
ZnO + 2HCl \to ZnC{l_2} + {H_2}O\\
{n_{{H_2}}} = 0,05mol\\
\to {n_{Zn}} = {n_{{H_2}}} = 0,05mol\\
\to {m_{Zn}} = 3,25g\\
\to {m_{ZnO}} = 5,95g \to {n_{ZnO}} = 0,07mol\\
a)\\
\% {m_{Zn}} = \dfrac{{3,25}}{{9,2}} \times 100\% = 35,33\% \\
\% {m_{ZnO}} = 100\% - 35,33\% = 64,67\% \\
b)\\
{n_{HCl}} = 2{n_{Zn}} + 2{n_{ZnO}} = 0,24mol\\
\to {m_{HCl}} = 8,76g\\
\to {m_{{\rm{dd}}HCl}} = \dfrac{{8,76}}{{14,6\% }} \times 100\% = 60g\\
c)\\
{m_{{\rm{dd}}thuđược}} = {m_{hỗnhợp}} + {m_{{\rm{dd}}HCl}} - {m_{{H_2}}} = 69,1g
\end{array}\)
